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Machine-Level Programming V: Miscellaneous Topics October 2, 2008
CISC 360 Machine-Level Programming V: Miscellaneous Topics October 2, 2008 Topics Linux Memory Layout Understanding Pointers Buffer Overflow Floating Point Code
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Linux Memory Layout Stack Heap DLLs Stack Data Text DLLs Heap Data
FF BF 7F 3F C0 80 40 00 Stack DLLs Text Data Heap 08 Linux Memory Layout Stack Runtime stack (8MB limit) Heap Dynamically allocated storage When call malloc, calloc, new DLLs Dynamically Linked Libraries Library routines (e.g., printf, malloc) Linked into object code when first executed Data Statically allocated data E.g., arrays & strings declared in code Text Executable machine instructions Read-only Upper 2 hex digits of address Red Hat v. 6.2 ~1920MB memory limit
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Linux Memory Allocation
Some Heap BF 7F 3F 80 40 00 Stack DLLs Text Data Heap 08 More Heap BF 7F 3F 80 40 00 Stack DLLs Text Data 08 Initially BF 7F 3F 80 40 00 Stack Text Data 08 Linked BF 7F 3F 80 40 00 Stack DLLs Text Data 08
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Text & Stack Example Initially Main Stack (gdb) break main (gdb) run
BF 7F 3F 80 40 00 Stack Text Data 08 (gdb) break main (gdb) run Breakpoint 1, 0x804856f in main () (gdb) print $esp $3 = (void *) 0xbffffc78 Main Address 0x804856f should be read 0x f Stack Address 0xbffffc78
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Dynamic Linking Example
Linked BF 7F 3F 80 40 00 Stack DLLs Text Data 08 (gdb) print malloc $1 = {<text variable, no debug info>} 0x <malloc> (gdb) run Program exited normally. $2 = {void *(unsigned int)} 0x <malloc> Initially Code in text segment that invokes dynamic linker Address 0x should be read 0x Final Code in DLL region
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Memory Allocation Example
char big_array[1<<24]; /* 16 MB */ char huge_array[1<<28]; /* 256 MB */ int beyond; char *p1, *p2, *p3, *p4; int useless() { return 0; } int main() { p1 = malloc(1 <<28); /* 256 MB */ p2 = malloc(1 << 8); /* 256 B */ p3 = malloc(1 <<28); /* 256 MB */ p4 = malloc(1 << 8); /* 256 B */ /* Some print statements ... */ }
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Example Addresses $esp 0xbffffc78 p3 0x500b5008 p1 0x400b4008
80 40 00 Stack DLLs Text Data Heap 08 $esp 0xbffffc78 p3 0x500b5008 p1 0x400b4008 Final malloc 0x p4 0x1904a640 p2 0x1904a538 beyond 0x1904a524 big_array 0x1804a520 huge_array 0x0804a510 main() 0x f useless() 0x Initial malloc 0x
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C operators Operators Associativity
() [] -> left to right ! ~ * & (type) sizeof right to left * / % left to right left to right << >> left to right < <= > >= left to right == != left to right & left to right ^ left to right | left to right && left to right || left to right ?: right to left = += -= *= /= %= &= ^= != <<= >>= right to left , left to right Note: Unary +, -, and * have higher precedence than binary forms
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C pointer declarations
int *p p is a pointer to int int *p[13] p is an array[13] of pointer to int int *(p[13]) p is an array[13] of pointer to int int **p p is a pointer to a pointer to an int int (*p)[13] p is a pointer to an array[13] of int int *f() f is a function returning a pointer to int int (*f)() f is a pointer to a function returning int int (*(*f())[13])() f is a function returning ptr to an array[13] of pointers to functions returning int int (*(*x[3])())[5] x is an array[3] of pointers to functions returning pointers to array[5] of ints
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Internet Worm and IM War
November, 1988 Internet Worm attacks thousands of Internet hosts. How did it happen? July, 1999 Microsoft launches MSN Messenger (instant messaging system). Messenger clients can access popular AOL Instant Messaging Service (AIM) servers AIM client MSN server MSN client AIM server AIM client
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Internet Worm and IM War (cont.)
August 1999 Mysteriously, Messenger clients can no longer access AIM servers. Microsoft and AOL begin the IM war: AOL changes server to disallow Messenger clients Microsoft makes changes to clients to defeat AOL changes. At least 13 such skirmishes. How did it happen? The Internet Worm and AOL/Microsoft War were both based on stack buffer overflow exploits! many Unix functions do not check argument sizes. allows target buffers to overflow.
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String Library Code Implementation of Unix function gets
No way to specify limit on number of characters to read Similar problems with other Unix functions strcpy: Copies string of arbitrary length scanf, fscanf, sscanf, when given %s conversion specification /* Get string from stdin */ char *gets(char *dest) { int c = getc(); char *p = dest; while (c != EOF && c != '\n') { *p++ = c; c = getc(); } *p = '\0'; return dest;
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Vulnerable Buffer Code
/* Echo Line */ void echo() { char buf[4]; /* Way too small! */ gets(buf); puts(buf); } int main() { printf("Type a string:"); echo(); return 0; }
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Buffer Overflow Executions
unix>./bufdemo Type a string:123 123 unix>./bufdemo Type a string:12345 Segmentation Fault unix>./bufdemo Type a string: Segmentation Fault
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Buffer Overflow Stack Return Address Saved %ebp [3] [2] [1] [0] buf %ebp Stack Frame for main for echo /* Echo Line */ void echo() { char buf[4]; /* Way too small! */ gets(buf); puts(buf); } echo: pushl %ebp # Save %ebp on stack movl %esp,%ebp subl $20,%esp # Allocate space on stack pushl %ebx # Save %ebx addl $-12,%esp # Allocate space on stack leal -4(%ebp),%ebx # Compute buf as %ebp-4 pushl %ebx # Push buf on stack call gets # Call gets
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Buffer Overflow Stack Example
unix> gdb bufdemo (gdb) break echo Breakpoint 1 at 0x (gdb) run Breakpoint 1, 0x in echo () (gdb) print /x *(unsigned *)$ebp $1 = 0xbffff8f8 (gdb) print /x *((unsigned *)$ebp + 1) $3 = 0x804864d Buffer Overflow Stack Example Return Address Saved %ebp [3] [2] [1] [0] buf %ebp Stack Frame for main for echo 0xbffff8d8 Return Address Saved %ebp [3] [2] [1] [0] buf Stack Frame for main for echo bf ff f8 08 04 86 4d xx Before call to gets : call c <echo> 804864d: mov 0xffffffe8(%ebp),%ebx # Return Point
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Buffer Overflow Example #1
Before Call to gets Input = “123” Return Address Saved %ebp [3] [2] [1] [0] buf %ebp Stack Frame for main for echo 0xbffff8d8 Return Address Saved %ebp [3] [2] [1] [0] buf Stack Frame for main for echo bf ff f8 08 04 86 4d 00 33 32 31 No Problem
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Buffer Overflow Stack Example #2
Return Address Saved %ebp [3] [2] [1] [0] buf %ebp Stack Frame for main for echo Input = “12345” 0xbffff8d8 Return Address Saved %ebp [3] [2] [1] [0] buf Stack Frame for main for echo bf ff 00 35 08 04 86 4d 34 33 32 31 Saved value of %ebp set to 0xbfff0035 Bad news when later attempt to restore %ebp echo code: : push %ebx : call e4 <_init+0x50> # gets : mov 0xffffffe8(%ebp),%ebx 804859b: mov %ebp,%esp 804859d: pop %ebp # %ebp gets set to invalid value 804859e: ret
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Buffer Overflow Stack Example #3
Return Address Saved %ebp [3] [2] [1] [0] buf %ebp Stack Frame for main for echo 0xbffff8d8 Return Address Saved %ebp [3] [2] [1] [0] buf Stack Frame for main for echo 38 37 36 35 08 04 86 00 34 33 32 31 Invalid address No longer pointing to desired return point Input = “ ” %ebp and return address corrupted : call c <echo> 804864d: mov 0xffffffe8(%ebp),%ebx # Return Point
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Malicious Use of Buffer Overflow
Stack after call to gets() void foo(){ bar(); ... } foo stack frame return address A B data written by gets() pad void bar() { char buf[64]; gets(buf); ... } exploit code bar stack frame B Input string contains byte representation of executable code Overwrite return address with address of buffer When bar() executes ret, will jump to exploit code
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Exploits Based on Buffer Overflows
Buffer overflow bugs allow remote machines to execute arbitrary code on victim machines. Internet worm Early versions of the finger server (fingerd) used gets() to read the argument sent by the client: finger Worm attacked fingerd server by sending phony argument: finger “exploit-code padding new-return-address” exploit code: executed a root shell on the victim machine with a direct TCP connection to the attacker.
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Exploits Based on Buffer Overflows
Buffer overflow bugs allow remote machines to execute arbitrary code on victim machines. IM War AOL exploited existing buffer overflow bug in AIM clients exploit code: returned 4-byte signature (the bytes at some location in the AIM client) to server. When Microsoft changed code to match signature, AOL changed signature location.
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Date: Wed, 11 Aug :30: (PDT) From: Phil Bucking Subject: AOL exploiting buffer overrun bug in their own software! To: Mr. Smith, I am writing you because I have discovered something that I think you might find interesting because you are an Internet security expert with experience in this area. I have also tried to contact AOL but received no response. I am a developer who has been working on a revolutionary new instant messaging client that should be released later this year. ... It appears that the AIM client has a buffer overrun bug. By itself this might not be the end of the world, as MS surely has had its share. But AOL is now *exploiting their own buffer overrun bug* to help in its efforts to block MS Instant Messenger. .... Since you have significant credibility with the press I hope that you can use this information to help inform people that behind AOL's friendly exterior they are nefariously compromising peoples' security. Sincerely, Phil Bucking Founder, Bucking Consulting It was later determined that this originated from within Microsoft!
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Code Red Worm History When We Set Up CS:APP Web Site
June 18, Microsoft announces buffer overflow vulnerability in IIS Internet server July 19, over 250,000 machines infected by new virus in 9 hours White house must change its IP address. Pentagon shut down public WWW servers for day When We Set Up CS:APP Web Site Received strings of form GET /default.ida?NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNN....NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNN%u9090%u6858%ucbd3%u7801%u9090%u6858%ucbd3%u7801%u9090%u6858%ucbd3%u7801%u9090%u9090%u8190%u00c3%u0003%u8b00%u531b%u53ff%u0078%u0000%u00=a HTTP/1.0" "-" "-"
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Code Red Exploit Code Starts 100 threads running Spread self
Generate random IP addresses & send attack string Between 1st & 19th of month Attack Send 98,304 packets; sleep for 4-1/2 hours; repeat Denial of service attack Between 21st & 27th of month Deface server’s home page After waiting 2 hours
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Code Red Effects Later Version Even More Malicious Paved Way for NIMDA
Code Red II As of April, 2002, over 18,000 machines infected Still spreading Paved Way for NIMDA Variety of propagation methods One was to exploit vulnerabilities left behind by Code Red II
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Avoiding Overflow Vulnerability
/* Echo Line */ void echo() { char buf[4]; /* Way too small! */ fgets(buf, 4, stdin); puts(buf); } Use Library Routines that Limit String Lengths fgets instead of gets strncpy instead of strcpy Don’t use scanf with %s conversion specification Use fgets to read the string
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IA32 Floating Point History Summary Floating Point Formats
8086: first computer to implement IEEE FP separate 8087 FPU (floating point unit) 486: merged FPU and Integer Unit onto one chip Summary Hardware to add, multiply, and divide Floating point data registers Various control & status registers Floating Point Formats single precision (C float): 32 bits double precision (C double): 64 bits extended precision (C long double): 80 bits Instruction decoder and sequencer Integer Unit FPU Memory
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FPU Data Register Stack
FPU register format (extended precision) s exp frac 63 64 78 79 FPU registers 8 registers Logically forms shallow stack Top called %st(0) When push too many, bottom values disappear “Top” %st(0) %st(1) %st(2) %st(3) stack grows down
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FPU instructions Large number of floating point instructions and formats ~50 basic instruction types load, store, add, multiply sin, cos, tan, arctan, and log! Sample instructions: Instruction Effect Description fldz push Load zero flds Addr push M[Addr] Load single precision real fmuls Addr %st(0) <- %st(0)*M[Addr] Multiply faddp %st(1) <- %st(0)+%st(1); pop Add and pop
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Floating Point Code Example
Compute Inner Product of Two Vectors Single precision arithmetic Common computation pushl %ebp # setup movl %esp,%ebp pushl %ebx movl 8(%ebp),%ebx # %ebx=&x movl 12(%ebp),%ecx # %ecx=&y movl 16(%ebp),%edx # %edx=n fldz # push +0.0 xorl %eax,%eax # i=0 cmpl %edx,%eax # if i>=n done jge .L3 .L5: flds (%ebx,%eax,4) # push x[i] fmuls (%ecx,%eax,4) # st(0)*=y[i] faddp # st(1)+=st(0); pop incl %eax # i++ cmpl %edx,%eax # if i<n repeat jl .L5 .L3: movl -4(%ebp),%ebx # finish movl %ebp, %esp popl %ebp ret # st(0) = result float ipf (float x[], float y[], int n) { int i; float result = 0.0; for (i = 0; i < n; i++) { result += x[i] * y[i]; } return result;
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Inner Product Stack Trace
Initialization 1. fldz 0.0 %st(0) Iteration 0 Iteration 1 2. flds (%ebx,%eax,4) 5. flds (%ebx,%eax,4) 0.0 %st(1) x[0]*y[0] %st(1) x[0] %st(0) x[1] %st(0) 3. fmuls (%ecx,%eax,4) 6. fmuls (%ecx,%eax,4) 0.0 %st(1) x[0]*y[0] %st(1) x[0]*y[0] %st(0) x[1]*y[1] %st(0) 4. faddp 7. faddp 0.0+x[0]*y[0] %st(0) %st(0) x[0]*y[0]+x[1]*y[1]
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Final Observations Memory Layout Type Declarations in C
OS/machine dependent (including kernel version) Basic partitioning: stack/data/text/heap/DLL found in most machines Type Declarations in C Notation obscure, but very systematic Working with Strange Code Important to analyze nonstandard cases E.g., what happens when stack corrupted due to buffer overflow Helps to step through with GDB IA32 Floating Point Strange “shallow stack” architecture
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Deadlines
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